The distance of the plane r · ( 2 7 i + 3 7 j - 6 7 k ) = 1 from the origin is:

Question

The distance of the plane $\vec{r} \cdot (\frac{2}{7} \hat{i} + \frac{3}{7} \hat{j} - \frac{6}{7} \hat{k}) = 1$ from the origin is:

Smart Achievers · Accepted Answer

(1)

Ans. 1

Explanation:

The distance of the plane $\vec{r} \cdot (\frac{2}{7} \hat{i} + \frac{3}{7} \hat{j} - \frac{6}{7} \hat{k}) = 1$ from the origin is $1$ .

[Since, $\vec{r} \cdot \vec{n} = d$ is the form of above equation, where $d$ represents the distance of plane from the origin i.e., $d = 1$ ]

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