The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude

Question

The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is:

Smart Achievers · Accepted Answer

(4)

$Time taken by the harmonic oscillator to move from mean position to half of the amplitude is \frac{T}{12}$

$so, \frac{T}{12} = 3$

$T = 36 sec$

Solution

Q.
The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is:

1 6s

2 8s

3 12s

4 36s

Ans.
(4)

$Time taken by the harmonic oscillator to move from mean position to half of the amplitude is \frac{T}{12}$

$so, \frac{T}{12} = 3$

$T = 36 sec$

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