The dimension of is equal to that of : ( = Vacuum permeability and = Vacuum permittivity) [2025]

Question

The dimension of $\sqrt{\frac{μ_{0}}{ε_{0}}}$ is equal to that of : ( $μ_{0}$ = Vacuum permeability and $ε_{0}$ = Vacuum permittivity) [2025]

Smart Achievers · Accepted Answer

(4)

$[μ_{0}] = [M L T^{- 2} A^{- 2}]$

$[ε_{0}] = [M^{- 1} L^{- 3} T^{4} A^{2}]$

$[\sqrt{\frac{μ_{0}}{ε_{0}}}] = [M L^{2} T^{- 3} A^{- 2}] ≃ [R]$

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