The degree of the differential equation [ 1 + ( d y d x ) 2 ] 3 / 2 = d 2ydx2 is:

Question

The degree of the differential equation ${[1 + {(\frac{d y}{d x})}^{2}]}^{3 / 2}$ $= \frac{d^{2} y}{d x^{2}}$ is

Smart Achievers · Accepted Answer

(4)

Ans. 2

Explanation:

Given that,

${[1 + {(\frac{d y}{d x})}^{2}]}^{3 / 2}$ $= \frac{d^{2} y}{d x^{2}}$

On squaring both sides, we get

${[1 + {(\frac{d y}{d x})}^{2}]}^{3}$ $=$ ${(\frac{d^{2} y}{d x^{2}})}^{2}$

So, the degree of differential equation is 2.

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