The critical point and nature for the function f(x,y)=x2-2x+y2+2y-2 is:
(4)
Ans. (1, - 1) min.
Explanation:
f(x,y)=x2-2x+y2+2y-2
Partial Derivatives
f'(x)=2x-2
and f'(y)=2y+2
Therefore, for critical points,
f'(x)=0
2x-2=0
⇒ x=1
and f'(y)=0
2y+2=0
⇒ y=-1
So, the critical point is (1,-1).
Now, f''(x)=2>0 and f''(y)=2>0
So at (1,-1).
(fx''×fy'')-fx'fy'=2×2-0=4>0