Q.

The coefficient of x17 in (1-x)13(1+x+x2)12 is

1 C612  
2 C79  
3 0  
4 1  

Ans.

(3)

We have,   (1-x)13(1+x+x2)12

=(1-x)[(1-x)(1+x+x2)]12=(1-x)(1-x3)12

In the expansion, all the powers of x is either in the form of 3k or (3k+1) for some k∈ℤ. But 17 has the form (3k+2).

∴   Coefficient of x17 in the given expansion is 0.