The charged particle moving in a uniform magnetic field of has an acceleration . The value of is

Question

The charged particle moving in a uniform magnetic field of $(3 \hat{i} + 2 \hat{j}) T$ has an acceleration $(4 \hat{i} - \frac{x}{2} \hat{j}) {m/s}^{2}$ . The value of $x$ is ________. [2026]

Smart Achievers · Accepted Answer

(12)

${\vec{F}}_{B} \propto (\vec{v} \times \vec{B}) \Rightarrow {\vec{F}}_{B} ⊥ \vec{B}$

$\vec{a} ⊥ \vec{B} \Rightarrow \vec{a} \cdot \vec{B} = 0$

$12 - x = 0 \Rightarrow x = 12$

Solution

Q.
The charged particle moving in a uniform magnetic field of $(3 \hat{i} + 2 \hat{j}) T$ has an acceleration $(4 \hat{i} - \frac{x}{2} \hat{j}) {m/s}^{2}$ . The value of $x$ is ________. [2026]

Ans.
(12)

${\vec{F}}_{B} \propto (\vec{v} \times \vec{B}) \Rightarrow {\vec{F}}_{B} ⊥ \vec{B}$

$\vec{a} ⊥ \vec{B} \Rightarrow \vec{a} \cdot \vec{B} = 0$

$12 - x = 0 \Rightarrow x = 12$

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Solution

Q. The charged particle moving in a uniform magnetic field of (3i^+2j^) T has an acceleration (4i^-x2j^) m/s2. The value of x is ________. [2026]

Ans. (12) F→B∝(v→×B→)⇒F→B⊥B→ a→⊥B→⇒a→·B→=0 12-x=0⇒x=12

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Q.
The charged particle moving in a uniform magnetic field of $(3 \hat{i} + 2 \hat{j}) T$ has an acceleration $(4 \hat{i} - \frac{x}{2} \hat{j}) {m/s}^{2}$ . The value of $x$ is ________. [2026]

Ans.
(12)

${\vec{F}}_{B} \propto (\vec{v} \times \vec{B}) \Rightarrow {\vec{F}}_{B} ⊥ \vec{B}$

$\vec{a} ⊥ \vec{B} \Rightarrow \vec{a} \cdot \vec{B} = 0$

$12 - x = 0 \Rightarrow x = 12$