The centre of a circle whose diameter’s end points are (–6, 3) and (6, 4) is:

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Solution

Q.
The centre of a circle whose diameter’s end points are (–6, 3) and (6, 4) is:

1 (8, –1)

2 (4, 7)

3 (0, 7/2)

4 (4, 7/2)

Ans.
(3)

We know that centre of a circle is the mid-point of the diameter.

Coordinates of the centre are:

$(\frac{- 6 + 6}{2}, \frac{3 + 4}{2}) = (0, \frac{7}{2})$

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