The centre of a circle is at (2, 0). If one end of a diameter is at (6, 0), then the other end is at :

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Solution

Q.
The centre of a circle is at (2, 0). If one end of a diameter is at (6, 0), then the other end is at :

1 (0, 0)

2 (4, 0)

3 (-2, 0)

4 (-6, 0)

Ans.
(3)

$(\frac{6 + x}{2}, \frac{0 + y}{2}) = (2, 0) \Rightarrow \frac{6 + x}{2} = 2, \frac{0 + y}{2} = 0$

⇒ x = –2 and y = 0

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