The area of a quadrant of a circle, whose circumference is 22 cm, is

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Solution

Q.
The area of a quadrant of a circle, whose circumference is 22 cm, is

1 $\frac{11}{8} c m^{2}$

2 $\frac{77}{8} c m^{2}$

3 $\frac{77}{2} c m^{2}$

4 $\frac{77}{4} c m^{2}$

Ans.
(2) $\frac{77}{8} c m^{2}$

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