The area enclosed between the curve y = x² + 2 and the X-axis between x = 0 and x = 3 is:

Question

The area enclosed between the curve $y = x^{2} + 2$ and the X-axis between $x = 0$ and $x = 3$ is:

Smart Achievers · Accepted Answer

(2)

Ans. 15 sq. units

Explanation:

$Area of LCBA = \int_{0}^{3} y d x$

$= \int_{0}^{3} (x^{2} + 2) d x$

$= {[\frac{x^{3}}{3} + 2 x]}_{0}^{3}$

$= \frac{27}{3} + 6 - 0$

$= 9 + 6 = 15 sq. units.$

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