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Solution

Q.
The angle of 1' (minute of arc) in radian is nearly equal to

1 $1.75 \times 10^{- 2} r a d$

2 $2.91 \times 10^{- 4} r a d$

3 $4.85 \times 10^{- 4} r a d$

4 $4.80 \times 10^{- 6} r a d$

Ans.
(b) $1^{'} = {(\frac{1}{60})}^{o} = \frac{1}{60} \times \frac{π}{180}$

$= 2.91 \times 10^{- 4} r a d$

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