The amount of glucose required to prepare 250 mL of M/20 aqueous solution is (Molar mass of glucose: 180 g ) [2024]

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Solution

Q.
The amount of glucose required to prepare 250 mL of M/20 aqueous solution is (Molar mass of glucose: 180 g ${mol}^{- 1}$ ) [2024]

1 2.25 g

2 4.5 g

3 0.44 g

4 1.125 g

Ans.
(1)

Molarity = $\frac{w \times 1000}{M \times V (mL)};$ $\frac{1}{20} = \frac{w \times 1000}{180 \times 250}$

$w = \frac{180 \times 250}{20 \times 1000}; w = 2.25$ $g$

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