The position of a particle is given by r→=3ti^+2t2j^+5k^, where t is in seconds and the coefficients have the proper units for r→ to be in metres. The acceleration of the particle at t = 1 s is
(3)
Given : r→=3ti^+2t2j^+5k^
Velocity, v→=dr→dt=ddt(3ti^+2t2j^+5k^)=3i^+4tj^ m s-1
v→=3i^+4tj^ m s-1
∴ Acceleration, a→=dv→dt=4j^ m s-2
Acceleration of the particle remains constant all the time.