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Solution


Q.

The 11th term from the end of the AP: 10, 7, 4, …, –62 is
1 25  
2 16  
3 -32  
4 0  

Ans.

(3)

Given AP is 10, 7, 4, …, –62.

∴nthterm from end=l-(n-1)d

Here,l=-62, d=7-10=-3

⇒11thterm from end =-62-(11-1)(-3)=-62+30=-32