tan - 1 3 - sec - 1 ( - 2 ) is equal to:

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Solution

Q.
$\tan^{- 1} \sqrt{3} - \sec^{- 1} (- 2)$ is equal to:

1 $π$

2 $- \frac{π}{3}$

3 $\frac{π}{3}$

4 $\frac{2 π}{3}$

Ans.
(2)

Ans. $- \frac{π}{3}$

Explanation:

$\tan^{- 1} \sqrt{3} - \sec^{- 1} (- 2)$

$= \tan^{- 1} \sqrt{3} - (π - \sec^{- 1} 2)$

$= \frac{π}{3} - π + \sec^{- 1} 2$

$= \frac{π}{3} - π + \frac{π}{3}$

$= \frac{2 π}{3} - π$

$= - \frac{π}{3}$

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