Surface tension of two liquids (having same densities), , are measured using capillary rise method utilizing two tubes with inner radii where. The measured liquid heights in these tubes are ? respectively. [Ignore the weight of the liquid about the lowes

Question

Surface tension of two liquids (having same densities), $T_{1} and T_{2}$ , are measured using capillary rise method utilizing two tubes with inner radii of $r_{1} and r_{2}$ where $r_{1} > r_{2}$ . The measured liquid heights in these tubes are $h_{1} and h_{2}$ respectively. [Ignore the weight of the liquid about the lowest point of meniscus.]

The heights $h_{1} and h_{2}$ and surface tensions $T_{1} and T_{2}$ satisfy the relation: [2026]

Smart Achievers · Accepted Answer

(2)

$h = \frac{2 T}{ρ g r}$

$h \propto \frac{1}{r}$

$If r_{1} > r_{2} \Rightarrow h_{2} > h_{1}$

Solution

1 $h_{1} > h_{2} and T_{1} < T_{2}$

2 $h_{1} < h_{2} and T_{1} = T_{2}$

3 $h_{1} > h_{2} and T_{1} = T_{2}$

4 $h_{1} = h_{2} and T_{1} = T_{2}$

Ans.
(2)

$h = \frac{2 T}{ρ g r}$

$h \propto \frac{1}{r}$

$If r_{1} > r_{2} \Rightarrow h_{2} > h_{1}$

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Solution

1 h1>h2​ and T1<T2

2 h1<h2 ​and T1=T2

3 h1>h2​ and T1=T2

4 h1=h2​ and T1=T2