Statement I: Stopping potential in photoelectric effect does not depend on the power of the light source. [2023]

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Q.
Given below are two statements: [2023]

Statement I: Stopping potential in photoelectric effect does not depend on the power of the light source.

Statement II: For a given metal, the maximum kinetic energy of the photoelectron depends on the wavelength of the incident light.

In the light of above statements, choose the most appropriate answer from the options given below.

1 Both Statement I and Statement II are incorrect

2 Statement I is correct but statement II is incorrect

3 Both statement I and statement II are correct

4 Statement I is incorrect but statement II is correct

Ans.
(3)

Stopping potential $V_{s} = \frac{K E_{\max}}{e}$

$V_{s} = \frac{\frac{h C}{λ} - ϕ}{e}$

Stopping potential does not depend on intensity or power of light used; it only depends on the frequency or wavelength of the incident light.

So both statements I and II are correct.

Solution

1 Both Statement I and Statement II are incorrect

2 Statement I is correct but statement II is incorrect

3 Both statement I and statement II are correct

4 Statement I is incorrect but statement II is correct

Ans.
(3)

Stopping potential $V_{s} = \frac{K E_{\max}}{e}$

$V_{s} = \frac{\frac{h C}{λ} - ϕ}{e}$

Stopping potential does not depend on intensity or power of light used; it only depends on the frequency or wavelength of the incident light.

So both statements I and II are correct.

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Solution

1 Both Statement I and Statement II are incorrect

2 Statement I is correct but statement II is incorrect

3 Both statement I and statement II are correct

4 Statement I is incorrect but statement II is correct

Ans. (3) Stopping potential Vs=KEmaxe Vs=hCλ-ϕe Stopping potential does not depend on intensity or power of light used; it only depends on the frequency or wavelength of the incident light. So both statements I and II are correct.

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Ans.
(3)

Stopping potential $V_{s} = \frac{K E_{\max}}{e}$

$V_{s} = \frac{\frac{h C}{λ} - ϕ}{e}$

Stopping potential does not depend on intensity or power of light used; it only depends on the frequency or wavelength of the incident light.

So both statements I and II are correct.