Statement-I: A point particle of mass moving with speed collides with a stationary point particle of mass . If the maximum energy loss possible is given as , then Statement-II: Maximum energy loss occurs when the particles get stuck together as a resu

Question

This question has statement I and statement II. Of the four choices given after the statements, choose the one that best describes the two statements. [2012]

Statement-I: A point particle of mass $m$ moving with speed $v$ collides with a stationary point particle of mass $M$ . If the maximum energy loss possible is given as $f (\frac{1}{2} m v^{2})$ , then $f = (\frac{m}{M + m}) .$

Statement-II: Maximum energy loss occurs when the particles get stuck together as a result of the collision.

Smart Achievers · Accepted Answer

(4)

Maximum energy loss $= \frac{P^{2}}{2 m} - \frac{P^{2}}{2 (m + M)}$ $[∵ K.E. = \frac{P^{2}}{2 m} = \frac{1}{2} m v^{2}]$

$= \frac{P^{2}}{2 m} [\frac{M}{(m + M)}] = \frac{1}{2} m v^{2} {\frac{M}{m + M}}$

Statement II is a case of perfectly inelastic collision.

By comparing the equation given in statement I with above equation, we get

$f = (\frac{M}{m + M}) instead of (\frac{m}{M + m})$

Hence statement I is wrong and statement II is correct.

Solution

1 Statement - I is true, Statement - II is true, Statement - II is the correct explanation of Statement - I.

2 Statement - I is true, Statement - II is true, Statement - II is not the correct explanation of Statement - I.

3 Statement - I is true, Statement - II is false.

4 Statement - I is false, Statement - II is true.

Want Us to Email you About Special Offers & Updates?