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Solution


Q.

Some couples participated in a mixed doubles badminton tournament. If the number of matches played, so that no couple played in a match, is 840, then the total numbers of persons, who participated in the tournament, is ___________ .            [2023]

Ans.

(16)

Let the total number of couples =n.

According to the question, C2n·C2n-2×2=840

⇒  n!2!(n-2)!×(n-2)!2!(n-4)!×2=840

⇒  n(n-1)(n-2)(n-3)2=840⇒n=8

∴  Total number of players=2×n=2×8=16