sin ( 3 - sin - 1 ( - 1 2 ) ) is equal to:

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Solution

Q.
$\sin (\frac{π}{3} - \sin^{- 1} (- \frac{1}{2}))$ is equal to:

1 $\frac{1}{\sqrt{2}}$

2 $\frac{1}{3}$

3 $\frac{\sqrt{3}}{2}$

4 $1$

Ans.
(4)

Ans. 1

Explanation:

$\sin [\frac{π}{3} - \sin^{- 1} (- \frac{1}{2})]$

$= \sin [\frac{π}{3} + \frac{π}{6}]$ $[∵ \sin^{- 1} (- \frac{1}{2}) = - \frac{π}{6}]$

$= \sin \frac{π}{2} = 1$

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