Refer to the circuit diagram given below. The heat generated across the $6 Ω$ resistance in 100 second is $\frac{α}{100} J$ . The value of $α$ is ______. (Nearest integer) [2026]

Question

Smart Achievers · Accepted Answer

(3477)

$i_{1} + i_{2} + i_{3} = 0$

$\frac{x - 0 - 3}{6} + \frac{x - 2}{3} + \frac{x - 0}{4} = 0 \Rightarrow x = \frac{14}{9} V$

$Current across 6 Ω = \frac{3 - (\frac{14}{9})}{6} = \frac{13}{54} A$

$H = {(\frac{13}{54})}^{2} \times 100 \times 6 = 34.77 = \frac{α}{100}$

$α = 3477$

Solution

Q.
Refer to the circuit diagram given below. The heat generated across the $6 Ω$ resistance in 100 second is $\frac{α}{100} J$ . The value of $α$ is ______. (Nearest integer) [2026]

Ans.
(3477)

$i_{1} + i_{2} + i_{3} = 0$

$\frac{x - 0 - 3}{6} + \frac{x - 2}{3} + \frac{x - 0}{4} = 0 \Rightarrow x = \frac{14}{9} V$

$Current across 6 Ω = \frac{3 - (\frac{14}{9})}{6} = \frac{13}{54} A$

$H = {(\frac{13}{54})}^{2} \times 100 \times 6 = 34.77 = \frac{α}{100}$

$α = 3477$

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Solution

Q. Refer to the circuit diagram given below. The heat generated across the 6 Ω resistance in 100 second is α100 J. The value of α is ______. (Nearest integer) [2026]

Ans. (3477) i1+i2+i3=0 x-0-36+x-23+x-04=0⇒x=149 V Current across 6Ω=3-(149)6=1354A H=(1354)2×100×6=34.77=α100 α=3477

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Q.
Refer to the circuit diagram given below. The heat generated across the $6 Ω$ resistance in 100 second is $\frac{α}{100} J$ . The value of $α$ is ______. (Nearest integer) [2026]

Ans.
(3477)

$i_{1} + i_{2} + i_{3} = 0$

$\frac{x - 0 - 3}{6} + \frac{x - 2}{3} + \frac{x - 0}{4} = 0 \Rightarrow x = \frac{14}{9} V$

$Current across 6 Ω = \frac{3 - (\frac{14}{9})}{6} = \frac{13}{54} A$

$H = {(\frac{13}{54})}^{2} \times 100 \times 6 = 34.77 = \frac{α}{100}$

$α = 3477$