Pressure inside a soap bubble is greater than the pressure outside by an amount

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Solution

Q.
Pressure inside a soap bubble is greater than the pressure outside by an amount

(Given: R = Radius of bubble, S = Surface tension of bubble) [2024]

1 $\frac{4 R}{S}$

2 $\frac{4 S}{R}$

3 $\frac{2 S}{R}$

4 $\frac{S}{R}$

Ans.
(2)

$P_{e x} = P_{i n} - P_{o u t}$

$P_{i n} = P_{o u t} + P_{e x}$

$P_{i n} = P_{o u t} + \frac{4 S}{R}$

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