Pressure inside a soap bubble is greater than the pressure outside by an amount:

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Solution

Q.
Pressure inside a soap bubble is greater than the pressure outside by an amount:

(given : R = Radius of bubble, S = Surface tension of bubble)

1 $\frac{S}{R}$

2 $\frac{4 S}{R}$

3 $\frac{3 R}{S}$

4 $\frac{6 R}{S}$

Ans.
(2)

$EXCESS PRESSURE = \frac{4 S}{R}$

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