PhCHO + HCHO ? (ii) H 3 O + (i) 50 ? N a O H A (major) + B (major) The compound formed on dehydration of A & B is

Question

$PhCHO + HCHO \to_{(ii) H_{3} O^{+}}^{(i) 50 % N a O H} \underset{_{(major)}}{A} + \underset{(major)}{B}$ The compound formed on dehydration of A & B is

Smart Achievers · Accepted Answer

(3)

$A = {PhCH}_{2} OH, B = HCOOH$

Solution

Q.
$PhCHO + HCHO \to_{(ii) H_{3} O^{+}}^{(i) 50 % N a O H} \underset{_{(major)}}{A} + \underset{(major)}{B}$ The compound formed on dehydration of A & B is

1 $Ph - CO - {OCH}_{3}$

2 $Ph - O - {COCH}_{3}$

3 $Ph - {CH}_{2} - O - CHO$

4 $Ph - {CH}_{2} - O - {CH}_{3}$

Ans.
(3)

$A = {PhCH}_{2} OH, B = HCOOH$

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Solution

Q. PhCHO+HCHO→(ii) H3O+(i) 50% NaOHA(major)+B(major) The compound formed on dehydration of A & B is

1 Ph-CO-OCH3

2 Ph-O-COCH3

3 Ph-CH2-O-CHO

4 Ph-CH2-O-CH3

Ans. (3) A=PhCH2OH, B=HCOOH

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Q.
$PhCHO + HCHO \to_{(ii) H_{3} O^{+}}^{(i) 50 % N a O H} \underset{_{(major)}}{A} + \underset{(major)}{B}$ The compound formed on dehydration of A & B is

1 $Ph - CO - {OCH}_{3}$

2 $Ph - O - {COCH}_{3}$

3 $Ph - {CH}_{2} - O - CHO$

4 $Ph - {CH}_{2} - O - {CH}_{3}$

Ans.
(3)

$A = {PhCH}_{2} OH, B = HCOOH$