Q.

One end of a horizontal uniform beam of weight W and length L is hinged on a vertical wall at point O and its other end is supported by a light inextensible rope. The other end of the rope is fixed at point Q, at a height L above the hinge at point O. A block of weight αW is attached at the point P of the beam, as shown in the figure (not to scale). The rope can sustain a maximum tension of (22)W. Which of the following statement(s) is(are) correct             [2021]

1 The vertical component of reaction force at O does not depend on α  
2 The horizontal component of reaction force at O is equal to W for α=0.5  
3 The tension in the rope is 2W for α=0.5  
4 The rope breaks if α>1.5  

Ans.

(1, 2, 4)

Since OQ=OP    P=Q=45°

At equilibrium, about point O,

Ry+T2=W+αW                         ...(i)

and   Rx=T2                                    ...(ii)

Torque about point 'O' is zero,

So, WL2+αWL=T2L     T=2(W2+αW)          ...(iii)

 Rx=T2=(W2+αW)

Therefore for α=0.5,

Rx=W2+αW=W2+0.5W  or  Rx=W

i.e., the horizontal component of reaction force at O,

Rx=W  for α=0.5

Now torque about point P,

TyL=W·L2    Ry=W2

The vertical component of reaction force at O does not depend on α.

As per question, rope can sustain a maximum tension of 22W,

 22W=2(W2+αW)

2=12+α

 α=32