Q.

Number of solutions of 3cos2θ+8cosθ+33=0, θ[-3π,2π] is:              [2026]

1 5  
2 0  
3 3  
4 4  

Ans.

(1)

3(2cos2θ-1)+8cosθ+33=0

23cos2θ+8cosθ+23=0

(3cosθ+1)(cosθ+3)=0

cosθ=-13

as -3 (reject)

θ will have 5 values in [-3π,2π]

Ans.=5option (1)