Number of molecules of H SO 2 4 present in 100 ml of 0.02M H SO 2 4 (assume no dissociation) solution is

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Solution

Q.
Number of molecules of $H_{2} S O_{4}$ present in $100 mL$ of $0.02 M$ $H_{2} S O_{4}$ (assume no dissociation) solution is _______

1 $12.044 \times 10^{20}$ molecules

2 $6.022 \times 10^{23}$ molecules

3 $1 \times 10^{23}$ molecules

4 $12.044 \times 10^{23}$ molecules

Ans.
(1)

$0.02 \times 100 \times 10^{- 23} \times 6.022 \times 10^{23} = 12.044 \times 10^{20}$

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