Nd 2 + = ____________ [2023]

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Solution

Q.
${Nd}^{2 +} =$ ____________ [2023]

1 $4 f^{3}$

2 $4 f^{4} 6 s^{2}$

3 $4 f^{2} 6 s^{2}$

4 $4 f^{4}$

Ans.
(4)

$Nd (Z = 60) = 4 f^{4} 6 s^{2}$

${Nd}^{2 +} = 4 f^{4}$

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