Molality of 0.8 M solution (density 1.06 g ) is ______ m.

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Solution

Q.
Molality of 0.8 M $H_{2} {SO}_{4}$ solution (density 1.06 g ${cm}^{- 3}$ ) is ______ $\times 10^{- 3}$ m. [2024]

Ans.
(815)

$m = \frac{M \times 1000}{d \times 1000 - M \times M_{solute}} = \frac{0.8 \times 1000}{1.06 \times 1000 - 0.8 \times 98} m$

$= 815 \times 10^{- 3} m$

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