Maximum number of atoms present in a plane in diborane is X. Maximum number of atoms present in a plane in Borazine is Y. Then, what is the value of $\frac{X + Y}{2}$

(Consider those planes which contain maximum number of atoms)

Question

Maximum number of atoms present in a plane in diborane is X. Maximum number of atoms present in a plane in Borazine is Y. Then, what is the value of $\frac{X + Y}{2}$ ?

(Consider those planes which contain maximum number of atoms)

Smart Achievers · Accepted Answer

(9)

$B_{2} H_{6} - 6 = x$

$B_{3} N_{3} H_{6} - 12 = y$

$\frac{x + y}{2} = \frac{18}{2} = 9$

Solution

Q.
Maximum number of atoms present in a plane in diborane is X. Maximum number of atoms present in a plane in Borazine is Y. Then, what is the value of $\frac{X + Y}{2}$

(Consider those planes which contain maximum number of atoms)

Ans.
(9)

$B_{2} H_{6} - 6 = x$

$B_{3} N_{3} H_{6} - 12 = y$

$\frac{x + y}{2} = \frac{18}{2} = 9$

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Solution

Q. Maximum number of atoms present in a plane in diborane is X. Maximum number of atoms present in a plane in Borazine is Y. Then, what is the value of X+Y2 (Consider those planes which contain maximum number of atoms)

Ans. (9) B2H6-6=x B3N3H6-12=y x+y2=182=9

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Q.
Maximum number of atoms present in a plane in diborane is X. Maximum number of atoms present in a plane in Borazine is Y. Then, what is the value of $\frac{X + Y}{2}$

(Consider those planes which contain maximum number of atoms)

Ans.
(9)

$B_{2} H_{6} - 6 = x$

$B_{3} N_{3} H_{6} - 12 = y$

$\frac{x + y}{2} = \frac{18}{2} = 9$