Match List–I with List–II.? Swarts reaction [2025]

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Q.
Match List–I with List–II. [2025]

List–I List–II

(Name reaction) (Product obtainable)

A. Swarts reaction I. Ethyl benzene

B. Sandmeyer’s reaction II. Ethyl iodide

C. Wurtz Fittig reaction III. Cyanobenzene

D. Finkelstein reaction IV. Ethyl fluoride

Choose the correct answer from the options given below:

1 A–IV, B–I, C–III, D–II

2 A–II, B–III, C–I, D–IV

3 A–IV, B–III, C–I, D–II

4 A–II, B–I, C–III, D–IV

Ans.
(3)

(A) $C_{2} H_{5} Cl \overset{AgF}{\to} \underset{Ethyl fluoride}{C_{2} H_{5} F} + AgCl$

(B)

(C)

(D) $C_{2} H_{5} Cl + NaI \to_{(Finkelstein reaction)}^{Acetone} C_{2} H_{5} I + NaCl$

Solution

1 A–IV, B–I, C–III, D–II

2 A–II, B–III, C–I, D–IV

3 A–IV, B–III, C–I, D–II

4 A–II, B–I, C–III, D–IV

Ans.
(3)

(A) $C_{2} H_{5} Cl \overset{AgF}{\to} \underset{Ethyl fluoride}{C_{2} H_{5} F} + AgCl$

(B)

(C)

(D) $C_{2} H_{5} Cl + NaI \to_{(Finkelstein reaction)}^{Acetone} C_{2} H_{5} I + NaCl$

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	List–I		List–II
	(Name reaction)		(Product obtainable)
A.	Swarts reaction	I.	Ethyl benzene
B.	Sandmeyer’s reaction	II.	Ethyl iodide
C.	Wurtz Fittig reaction	III.	Cyanobenzene
D.	Finkelstein reaction	IV.	Ethyl fluoride

Solution

1 A–IV, B–I, C–III, D–II

2 A–II, B–III, C–I, D–IV

3 A–IV, B–III, C–I, D–II

4 A–II, B–I, C–III, D–IV

Ans. (3) (A) C2H5Cl→AgFC2H5FEthyl fluoride+AgCl (B) (C) (D) C2H5Cl+NaI→(Finkelstein reaction)AcetoneC2H5I+NaCl

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Ans.
(3)

(A) $C_{2} H_{5} Cl \overset{AgF}{\to} \underset{Ethyl fluoride}{C_{2} H_{5} F} + AgCl$

(B)

(C)

(D) $C_{2} H_{5} Cl + NaI \to_{(Finkelstein reaction)}^{Acetone} C_{2} H_{5} I + NaCl$