Match List I with List II | jee main chemistry important questions | Coordination Compounds jee main questions

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Solution

Q.
Match List I with List II.

List I List II

Tetrahedral Complex Electronic Configuration

A. ${TiCl}_{4}$ I. $e^{2}, t_{2}^{0}$

B. ${[{FeO}_{4}]}^{2 -}$ II. $e^{4}, t_{2}^{3}$

C. ${[{FeCl}_{4}]}^{-}$ III. $e^{0}, t_{2}^{0}$

D. ${[{CoCl}_{4}]}^{2 -}$ IV. $e^{2}, t_{2}^{3}$

Choose the correct answer from the options given below: [2024]

1 (A) - (III), (B) - (I), (C) - (IV), (D) - (II)

2 (A) - (III), (B) - (IV), (C) - (II), (D) - (I)

3 (A) - (IV), (B) - (III), (C) - (I), (D) - (II)

4 (A) - (I), (B) - (III), (C) - (IV), (D) - (II)

Ans.
(1)

Complex Electronic
configuration of central
metal without tetrahedral
splitting
Electronic
configuration of central
metal with tetrahedral splitting

${TiCl}_{4}$ ${Ti}^{4 +} = {}_{18}{[Ar]} 3 d^{0} 4 s^{0}$ $e^{0, 0}, t_{2}^{0, 0, 0}$

${[{FeO}_{4}]}^{2 -}$ ${Fe}^{6 +} = {}_{18}{[Ar]} 3 d^{2} 4 s^{0}$ $e^{1, 1}, t_{2}^{0, 0, 0}$

$[{FeCl}_{4}^{-}]$ ${Fe}^{3 +} = {}_{18}{[Ar]} 3 d^{5} 4 s^{0}$ $e^{1, 1}, t_{2}^{1, 1, 1}$

${[{CoCl}_{4}]}^{2 -}$ ${Co}^{2 +} = {}_{18}{[Ar]} 3 d^{7} 4 s^{0}$ $e^{2, 2}, t_{2}^{1, 1, 1}$

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