Q.

Let f:R→R and g:R→R be defined as:

f(x)={logex,x>0e-x,x≤0 and g(x)={x,x≥0ex,x<0.

Then, gof:R→R is                                                                            [2024]

1 neither one-one nor onto  
2 onto but not one-one  
3 one-one but not onto  
4 both one-one and onto  

Ans.

(1)

 g(f(x)) ={f(x),f(x)≥0ef(x),f(x) < 0

={logex,x≥1e-x,x≤0elogex=x, 0<x<1 

gof(x)={e-x ,x≤0x ,0<x<1logex,x≥1

Now, range of gof=[0,∞)≠R

Hence, not one-one and not onto.