Q.

Let y=f(x) satisfy the differential equation dydx=2xe-y, ∀x∈R. If y'(1)=1 then the number of solutions of the equation f(x)=f'(x) in (0,∞) is

1 1  
2 2  
3 3  
4 zero  

Ans.

(1)

∫ey dy=∫2x dx⇒f(x)=ln(x2+c)

f'(1)=1⇒C=1