Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x) = sec – 1 (2[x] + 1) is : [2025]

Question

Let [x] denote the greatest integer less than or equal to x. Then the domain of f(x) = $\sec^{- 1}$ (2[x] + 1) is : [2025]

Smart Achievers · Accepted Answer

(1)

We have, $2 [x] + 1 \leq - 1 or 2 [x] + 1 \geq 1$

$\Rightarrow [x] \leq - 1 or [x] \geq 0$

$\Rightarrow x \in (- \infty, 0) or x \in [0, \infty)$

$\Rightarrow x \in (- \infty, \infty)$

Want Us to Email you About Special Offers & Updates?