Q.

Let the vectors a→,b→,c→ represent three coterminous edges of a parallelepiped of volume V. Then the volume of the parallelepiped whose coterminous edges are represented by a→,b→+c→ and a→+2b→+3c→ is equal to         [2023]

1 V  
2 3V  
3 2V  
4 6V  

Ans.

(1)

We have, 

Volume of parallelepiped=[a→b→c→]=V                 ...(i)

New volume of parallelepiped =[a→b→+c→a→+2b→+3c→]

=|100011123|[a→b→c→]={1(3-2)-0+0}[a→b→c→]

=[a→b→c→]=V                    (Using (i))