Q.

Let the distance between two parallel lines be 5 units and a point P lie between the lines at a unit distance from one of them. An equilateral triangle PQR is formed such that Q lies on one of the parallel lines, while R lies on the other. Then (QR)2 is equal to _________.          [2025]


Ans.

(28)

Let ∠PRN=θ

⇒ PR=cosec θ and PQ=4 sec(30°+θ)

For equilateral △PQR.

Let PR = PQ

⇒ cosec θ=4 sec(θ+30°)

⇒ cos (θ+30°)=4 sin θ

⇒ 32cos θ–12sin θ=4 sin θ

⇒ tan θ=133

⇒ cosecθ=28

Now, QR2=d2=cosec2θ=28.