Let [t] denote the greatest integer function. If ∫02.4[x2] dx=α+β2+γ3+δ5, then α+β+γ+δ is equal to _________ . [2023]
(6)
We have,
∫02.4[x2] dx=∫010dx+∫121dx+∫232dx+∫323dx+∫254dx+∫52.45dx
=2-1+2(3-2)+3(2-3)+4(5-2)+5(2.4-5)
=9-2-3-5
∴ α+β+γ+δ =9-1-1-1=6