Let S be the set of all (α,β)∈ℝ×ℝ such that limx→∞sin(x2)(logex)αsin(1x2)xαβ(loge(1+x))β=0.
Then which of the following is (are) correct [2024]
(2, 3)
Given, limx→∞sin(x2)sin(1x2)(lnx)αxαβ(ln(1+x))β=0
=limx→∞(sinx2)sin(1x2)1x2(lnx)α(1x2)xαβ(ln(1+x))β=0
=limx→∞(lnxln(1+x))β·(lnx)α-βxαβ+2=0
=limx→∞(lnx)α-βxαβ+2=0
It is possible if αβ+2>0 αβ>-2