Q.

Let S be the set of all (α,β)× such that limxsin(x2)(logex)αsin(1x2)xαβ(loge(1+x))β=0.

Then which of the following is (are) correct            [2024]

1 (-1,3)S  
2 (-1,1)S  
3 (1,-1)S  
4 (1,-2)S  

Ans.

(2, 3)

 Given,    limxsin(x2)sin(1x2)(lnx)αxαβ(ln(1+x))β=0

=limx(sinx2)sin(1x2)1x2(lnx)α(1x2)xαβ(ln(1+x))β=0

=limx(lnxln(1+x))β·(lnx)α-βxαβ+2=0

=limx(lnx)α-βxαβ+2=0

It is possible if αβ+2>0  αβ>-2