Q.

Let R2 denote R×R. Let S={(a,b,c):a,b,c∈R and ax2+2bxy+cy2>0 for all (x,y)∈R2-{(0,0)}. Then which of the following statements is (are) TRUE        [2024]

1 (2,72,6)∈S  
2 If (3,b,112)∈S, then |2b|<1.  
3 For any given (a,b,c)∈S, the system of linear equations ax+by=1, by+cy=-1 has a unique solution.  
4 For any given (a,b,c)∈S, the system of linear equations (a+1)x+by=0, bx+(c+1)y=0 has a unique solution.  

Ans.

(2, 3, 4)

Given that ax2+2bxy+cy2>0

and x,y∈ℝ-{0}

⇒c(yx)2+2b(yx)+a>0⇒c>0, D<0

4b2-4ac<0⇒b2<ac

(1)  (2,72,6)
         (72)2>2×6
        ∴ Option (1) is incorrect

(2)  If (3,b,112)∈S
         ⇒b2<3·112⇒b2<14⇒4b2<1
          ⇒|2b|<1  Option (2) is correct

(3)  ax+by=1

         bx+cy=-1

          D=|abbc|=ac-b2≠0

        ∴ unique solution, option (3) is correct

(4)  (a+1)x+by=0

          bx+(c+1)y=0

          D=|a+1bbc+1|

          =(a+1)(c+1)-b2=ac-b2+a+c+1

           Since ac-b2>0⇒b2<ac⇒ac is positive

           ⇒a and c are positive, then (ac-b2)+a+c+1>0

            ∴ unique solution⇒option (4) is correct