Let R2 denote R×R. Let S={(a,b,c):a,b,c∈R and ax2+2bxy+cy2>0 for all (x,y)∈R2-{(0,0)}. Then which of the following statements is (are) TRUE [2024]
(2, 3, 4)
Given that ax2+2bxy+cy2>0
and x,y∈ℝ-{0}
⇒c(yx)2+2b(yx)+a>0⇒c>0, D<0
4b2-4ac<0⇒b2<ac
(1) (2,72,6) (72)2>2×6 ∴ Option (1) is incorrect
(2) If (3,b,112)∈S ⇒b2<3·112⇒b2<14⇒4b2<1 ⇒|2b|<1 Option (2) is correct
(3) ax+by=1
bx+cy=-1
D=|abbc|=ac-b2≠0
∴ unique solution, option (3) is correct
(4) (a+1)x+by=0
bx+(c+1)y=0
D=|a+1bbc+1|
=(a+1)(c+1)-b2=ac-b2+a+c+1
Since ac-b2>0⇒b2<ac⇒ac is positive
⇒a and c are positive, then (ac-b2)+a+c+1>0
∴ unique solution⇒option (4) is correct