Q.

Let M and N be two 3×3 matrices such that MN=NM. Further, if M≠N2 and M2=N4, then             [2014]

1 determinant of (M2+MN2) is 0  
2 There is a 3×3 non-zero matrix U such that (M2+MN2)U is the zero matrix  
3 determinant of (M2+MN2)≥1  
4 For a 3×3 matrix U, if (M2+MN2)U equals the zero matrix, then U is the zero matrix  

Ans.

(1, 2)

Given: MN=NM, M≠N2 and M2=N4

Then, M2=N4⇒(M+N2)(M-N2)=0

⇒(i)  M+N2=0 and M-N2≠0,

     (ii)  |M+N2|≠0 and |M-N2|=0

In each case, |M+N2|=0

∴ |M2+MN2|=|M||M+N2|=0

∴ (1) is correct and (3) is not correct.

Also, we know if |A|=0, then there can be many matrices U, such that AU=0

∴ (M2+MN2)U=0 will be true for many values of U.

∴ (2) is correct.

Again, if AX=0 and |A|=0, then X can be non-zero.

∴ (4) is not correct.