Let L be a normal to the parabola y2=4x. If L passes through the point (9, 6), then L is given by [2011]
(1, 2, 4)
The equation of normal to y2=4x is y=mx-2m-m3
Since the normal passes through (9, 6), ∴ 6=9m-2m-m3
⇒m3-7m+6=0⇒(m-1)(m2+m-6)=0
⇒(m-1)(m+3)(m-2)=0⇒m=1,2,-3
∴ Normals are y-x+3=0 or y-2x+12=0 or y+3x-33=0