Q.

Let L be a normal to the parabola y2=4x. If L passes through the point (9, 6), then L is given by                [2011]

1 y-x+3=0    
2 y+3x-33=0  
3 y+x-15=0    
4 y-2x+12=0  

Ans.

(1, 2, 4)

The equation of normal to y2=4x is y=mx-2m-m3

Since the normal passes through (9, 6),  6=9m-2m-m3

m3-7m+6=0(m-1)(m2+m-6)=0

(m-1)(m+3)(m-2)=0m=1,2,-3

 Normals are y-x+3=0 or y-2x+12=0 or y+3x-33=0