Let ∑k=1nak=αn2+βn. If a10=59 and a6=7a1, then α+β is equal to [2026]
(4)
an=Sn-Sn-1
=(αn2+βn)-(α(n-1)2+β(n-1))
(1) a59⇒19α+β=59
(2) a6=7a1⇒11α+β=7(α+β)
⇒2α=3β
α=3, β=2
α+β=5