Let f(x) = x2 + bx + c, minimum value of f(x) is -5, then absolute value of the difference of the roots of f(x) is:

Question

Let $f (x) = x^{2} + b x + c$ , minimum value of $f (x)$ is $- 5$ , then absolute value of the difference of the roots of $f (x)$ is:

Smart Achievers · Accepted Answer

(2)

$Minimum value \frac{- D}{4} = - 5 \Rightarrow D = 20$

$| α - β |$ $= \frac{\sqrt{D}}{1} = \sqrt{20}$

Want Us to Email you About Special Offers & Updates?