Let f(x)=xsin(πx), x>0. Then for all natural numbers n, f'(x) vanishes at [2013]
(2, 3)
Given: f(x)=xsinπx, x>0
⇒f'(x)=sinπx+xπcosπx
Now, f'(x)=0⇒tanπx=-πx
From graph of y=tanπx and y=-πx, it is clear that they intersect each other at a unique point in the intervals
(n,n+1) and (n+12, n+1)