Let f(x)=[x]2-[x+3]-3, x∈ℝ, where [·] is the greatest integer function. Then: [2026]
(1)
f(x)=[x]2-[x]-6=([x]+2)([x]-3)
(1) f(x)>0⇒[x]∈(-∞,-2)∪(3,∞)
⇒x∈(-∞,-2)∪[4,∞)
(2) f(x)<0⇒[x]∈(-2,3)
⇒x∈[-1,3)
option (2) is correct
(3) ∫02f(x)dx=∫01(0-0-6)dx+∫12(1-1-6)dx
=-6-6
=-12
(4) f(x)=0⇒[x]=3 or [x]=-2
infinitely many solutions