Q.

Let f(x)=sin(πcosx) and g(x)=cos(2πsinx) be two functions defined for x>0. Define the following sets whose elements are written in the increasing order.

X={x:f(x)=0},  Y={x:f'(x)=0}

Z={x:g(x)=0},  W={x:g'(x)=0}

Column - I contains the sets X, Y, Z and W. Column - II contains some information regarding these sets.             [2019]

  Column I   Column II
(I) X (p) ⊇{π2,3π2,4π,7π}
(II) Y (q) an arithmetic progression
(III) Z (r) NOT an arithmetic progression
(IV) W (s) ⊇{π6,7π6,13π6}
    (t) ⊇{π3,2π3,π}
    (u) ⊇{π6,3π4}

 

Which of the following is the only CORRECT combination

1 (I), (q), (u)  
2 (I), (p), (r)  
3 (II), (r), (s)  
4 (II), (q), (t)  

Ans.

(4)

f(x)=0⇒sin(πcosx)=0⇒πcosx=nπ

⇒cosx=n⇒cosx=-1,0,1

⇒x=π2,π,3π2,2π,5π2,3π,7π2,4π,…

∴ X={π2,π,3π2,2π,5π2,3π,7π2,4π,…}

∴ (I)→P,Q

f'(x)=0⇒cos(πcosx)(-πsinx)=0

⇒cos(πcosx)=0, sinx=0

⇒πcosx=(2n-1)π2, x=nπ

⇒cosx=2n-12, x=π,2π,3π,…

⇒cosx=-12,12

⇒x=π3,2π3,4π3,5π3,7π3,8π3,10π3,11π3,13π3,…

∴ Y={π3,2π3,π,4π3,5π3,2π,…}

∴ (II)→Q,T

g(x)=0⇒cos(2πsinx)=0

⇒2πsinx=(2n-1)π2⇒sinx=2n-14

⇒sinx=14,-14,34,-34

∴ Z={-sin-114,-sin-134,sin-114,sin-134}

∴ (III)→R

g'(x)=0⇒-sin(2πsinx)·2πcosx=0

⇒sin(2πsinx)=0, cosx=0

⇒2πsinx=nπ, x=(2n-1)π2

⇒sinx=n2, x=π2,3π2,5π2,7π2,…

⇒sinx=-1,-12,0,12,1

⇒x=π6,π2,5π6,π,3π2,11π6,2π,13π6,…

∴ W={π6,π2,5π6,π,3π2,11π6,2π,13π6,…}

∴ (IV)→P,R,S