Q.

Let f(x)=limθ→0(cos(πx)-x(2θ)sin(x-1)1+x(2θ)(x-1)),  x∈ℝ.

Consider the following two statements:

I. f(x) is discontinuous at x = 1

II. f(x) is continuous at x = -1

Then,  [2026]

1 Only (I) is True  
2 Only (II) is True  
3 Neither (I) nor (II) is True  
4 Both (I) and (II) are True  

Ans.

(3)

f(x)={cos(πx)x→1--sin(x-1)x-1x→1+

RHL=limx→1-sin(x-1)x-1=-1

LHL=limx→1cos(πx)=-1,  f(1)=-1

f(x) is continuous at x=1

f(x)={-sin(x-1)-(x-1)x→-1-cos(πx)x→-1+

RHL=limx→-1cos(πx)=-1

LHL=limx→-1-sin(x-1)x-1=sin2-2

f(x) is discontinuous at x=-1