Let f ( x ) = { 2 - | x 2 + 5 x + 6 | x - 2 b 2 + 1 x = - 2 Has relative maximum at x = - 2 , then complete set of values ' b ' can take is:

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Solution

Q.
Let $f (x) =$ ${\begin{matrix} 2 - | x^{2} + 5 x + 6 | & x \neq - 2 \\ b^{2} + 1 & x = - 2 \end{matrix}$

Has relative maximum at $x = - 2$ , then complete set of values $' b'$ can take is:

1 $| b |$ $\geq 1$

2 $| b |$ $< 1$

3 $b > 1$

4 $b < 1$

Ans.
(1)

$b^{2} + 1 \geq 2$

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